Shape Forms

Shape Forms - So in your case, since the index value of y.shape[0] is 0, your are. Objects cannot be broadcast to a single shape it computes the first two (i am running several thousand of these tests in a. 82 yourarray.shape or np.shape() or np.ma.shape() returns the shape of your ndarray as a tuple; You can think of a placeholder in tensorflow as an operation specifying the shape and type of data that will be fed into the graph.placeholder x defines. (r,) and (r,1) just add (useless). Shape is a tuple that gives you an indication of the number of dimensions in the array. And you can get the (number of) dimensions.

Objects cannot be broadcast to a single shape it computes the first two (i am running several thousand of these tests in a. (r,) and (r,1) just add (useless). And you can get the (number of) dimensions. 82 yourarray.shape or np.shape() or np.ma.shape() returns the shape of your ndarray as a tuple; So in your case, since the index value of y.shape[0] is 0, your are. Shape is a tuple that gives you an indication of the number of dimensions in the array. You can think of a placeholder in tensorflow as an operation specifying the shape and type of data that will be fed into the graph.placeholder x defines.

You can think of a placeholder in tensorflow as an operation specifying the shape and type of data that will be fed into the graph.placeholder x defines. So in your case, since the index value of y.shape[0] is 0, your are. Objects cannot be broadcast to a single shape it computes the first two (i am running several thousand of these tests in a. 82 yourarray.shape or np.shape() or np.ma.shape() returns the shape of your ndarray as a tuple; And you can get the (number of) dimensions. Shape is a tuple that gives you an indication of the number of dimensions in the array. (r,) and (r,1) just add (useless).

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Shape Is A Tuple That Gives You An Indication Of The Number Of Dimensions In The Array.

You can think of a placeholder in tensorflow as an operation specifying the shape and type of data that will be fed into the graph.placeholder x defines. So in your case, since the index value of y.shape[0] is 0, your are. Objects cannot be broadcast to a single shape it computes the first two (i am running several thousand of these tests in a. (r,) and (r,1) just add (useless).

82 Yourarray.shape Or Np.shape() Or Np.ma.shape() Returns The Shape Of Your Ndarray As A Tuple;

And you can get the (number of) dimensions.

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